Question

A Hypothetical reaction, 2p+q→s+r has rate constant as 2.0 х 10¯³ mole L¯¹sec¯¹. The order of the reaction is​

Answer 1

Explanation:

Rate constant for first order reaction is independent of initial concentration. Thus,

k=0.25s

−1

Answer 2

Given:

The reaction, 2p+q→s+r has a rate constant of 2.0 х 10¯³ mole L¯¹sec¯¹.

To Find:

The order of the reaction.

Solution:

According to the formula for the rate constant, we know that:

Rate constant

$= { \frac{(concentration)}{time}}^{1 - n}$

Here, n is the order of the reaction.

So, equating the units of the rate constant from the question we get,

${ \frac{(concentration)}{time}}^{1 - n} = mole L¯¹sec¯¹$

As we know concentration = mole L¯¹sec¯¹

Now,

${ \frac{( \: mole L¯¹)}{sec}}^{1 - n} = mole L¯¹sec¯¹$

${(mole L¯¹sec¯¹)}^{1 -n } = mole L¯¹sec¯¹$ Left-hand side will be equal to the right-hand side only when n= 1

Henceforth, the order of the reaction is 1.