A hypothetical Thermodynamic Cycle is shown in figure. Calculate the work done in 25 cycles.
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Answer:
7.85 × 10^4 J
Explanation:
Work done in 1 cycle = Area enclosed
by the PV curve.
= π/4 × (P2 - P1)(V2 - V1)
= π/4 × [(11 - 1)× 10^5][(6 - 2)× 10^-3]
= π/4 × (10^6)(4 × 10^-3)
= π × 10^3
= 3.14 × 10^3 J
→→→→ WORK DONE in 25 CYCLES
= 25×3.14×10^3
= 7.85 × 10^4 J.
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