Question

A=i+4j+2k b=3i-2j+7k find a vector whose magnitude is equal to that of b

Answer 1

Answer:

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Step-by-step explanation:

||a||=√(3)2+(−2)2+(1)2=√14

||b||=√(−2)2+(2)2+(4)2=√24=2√6

Angle between a and b:

a⋅b=(3−2+1)(−2+2+4)=−6

−6=√14⋅2√6⋅cos(θ)

cos(θ)=−6√14⋅2√6=−3√84=−3√8484

θ=arccos(−3√8484)=109.11