A(i) find the smallest number by which 1323 must be multiply so that the product is a perfect cube.(ii) What is the smallest number by which 1600 must be divided so that the question is a perfect cube? (iii) The volume of a cubical box is13.824 cubic meters .find the length of each side of the box.
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(i) 1323 = 3 * 3 * 3 * 7 * 7
= 3^3 * 7^2.
In this factorization, there is no triplet for 7.
So 1323 is not a perfect cube.
To make it a perfect cube it be multiplied by 7.
(ii) 1600 = 2 * 2 * 2 * 2 * 2 * 2 * 5 * 5
= (2^3) * (2^3) * 5^2
= (2 * 2)^3 * 5^2
In this factorization, there is no triplet for 5.
So it is not a perfect cube.
To make it a perfect cube it should be divided by 25.
(iii) Given volume of a cube = 13.824 m^3.
Let the side of the cube = x.
We know that volume of a cube = s^3
x^3 = 13.824
x = 2.4.
The length of each side of the box = 2.4m.
Hope this helps!
= 3^3 * 7^2.
In this factorization, there is no triplet for 7.
So 1323 is not a perfect cube.
To make it a perfect cube it be multiplied by 7.
(ii) 1600 = 2 * 2 * 2 * 2 * 2 * 2 * 5 * 5
= (2^3) * (2^3) * 5^2
= (2 * 2)^3 * 5^2
In this factorization, there is no triplet for 5.
So it is not a perfect cube.
To make it a perfect cube it should be divided by 25.
(iii) Given volume of a cube = 13.824 m^3.
Let the side of the cube = x.
We know that volume of a cube = s^3
x^3 = 13.824
x = 2.4.
The length of each side of the box = 2.4m.
Hope this helps!
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