A= i+j+k and B= i+j-k. find the angle between A and B
Answers
Answered by
0
Answer:
Explanation:We're asked to find the angle between two vectors, given their unit vector notations.
To do this, we can use the equation
→
A
⋅
→
B
=
A
B
cos
θ
rearranging to solve for angle,
θ
:
cos
θ
=
→
A
⋅
→
B
A
B
θ
=
arccos
⎛
⎝
→
A
⋅
→
B
A
B
⎞
⎠
where
→
A
⋅
→
B
is the dot product of the two vectors, which is
→
A
⋅
→
B
=
A
x
B
x
+
A
y
B
y
+
A
z
B
z
=
(
1
)
(
1
)
+
(
1
)
(
1
)
+
(
1
)
(
0
)
=
2
A
and
B
are the magnitudes of vectors
→
A
and
→
B
, which are
A
=
√
1
2
+
1
2
+
1
2
=
√
3
B
=
√
1
2
+
1
2
+
0
2
=
√
2
Therefore, we have
θ
=
arccos
(
2
√
3
√
2
)
=
arccos
(
2
√
6
)
=
35.3
o
Similar questions