Question

(a+ib) (1+I) = 2 + I (i = imaginary number)​

Answer 1

Step-by-step explanation:

(a+ ib) (1+l) = 2+l

= (a+la) (ib+ibl)

= (iab+aibl+laib+l^2aib)

= {(2laib)+iab+l^2aib}