(a+ib) (c+id) = A+iB show that (a²+b²) (c²+d²) =A²+B²
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helo guys its your answer
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If a+ib/c+id=x+iy prove that X² +y²=a²+b²/c²+d² Get the (a2 + b2) (c2 + d2 ) (e2 + f2 ) (g2 ...
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