Question

A ice piece of 40g at -10°C temperature is dropped in a water of 100g at 30°C. What is the final temperature of the mixture? ( Latent heat of fusion of ice = 80 cal/g and sp.heat of ice = 0.55)
Hints : use principle of calorimetry​

Answer 1

heat heat release is equals to heat gain

q1=q2

msdelta T= mL+ msdelta T

hence answer is 0°C

because while solving we will get -170/19

which is not possible

because the final T cannot be negative

this means that all the I e is not converted into ice

hence answer= 0°C