A ideal gas undergoes a thermodynamic cycle which when represented on T-S diagram is a circle with maximum and minimum temperatures of 600 K and 300 K. What is its efficiency
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Answer:
the efficiency of the above cycle is 41.5%
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Refer the pic.
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Efficiency is 41.5%.
Given:
Ideal gas undergoes a thermodynamic cycle which when represented on the T-S diagram is a circle with maximum and minimum temperatures of 600 K and 300 K.
To Find:
The efficiency of the Ideal gas.
Solution:
We know that the area under TS Curve gives heat.
In the curve it is cyclic, hence it gives net heat.
According to the second law :
In cyclic Net Heat = Net Work
ФH = Фω
Here,
ω = π
ω = π ()
ω = 70.685KJ
Q = Heat input = 1/2 π + 450 x 300
Q = 35.343 + 135
Q = 170.343 KJ
η = ω / Q
η = 70.685 / 170.343
η = 41.5%
Therefore the efficiency of the given ideal gas is 41.5%
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