Question

(a) If 2 + 2 tan 0 = sec? o, find the value of tan 0.



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Answer 1

Answer:

Solution

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secθ+tanθ=32 .. (1)

sec2θ−tan2θ=1

(secθ+tanθ)(secθ−tanθ)=1

⇒secθ−tanθ=secθ+tanθ1

secθ−tanθ=23 ... (2)

Add equation (1) and (2),

2secθ=32+23=613

secθ=1213

From (1),

tanθ=32−secθ=−125

sinθ=secθtanθ=−135

Step-by-step explanation:

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