Math, asked by shahkajal623, 10 months ago


a)
If 4700 bricks each of size 25 cm x 16 cm x 10 cm are required to construct a wall
20 m long and 20 cm wide containing two windows of size 2 m x 1.5 m each, find
the height of the wall.​

Answers

Answered by asheem445
2

Step-by-step explanation:

Solution

Area of wall = length of wall * breadth of wall

= (20*100 cm) * 20cm

= 2000 cm × 20 cm

= 40000 cm^2

Area of window = length of window * breadth of

window

= 2 × 1.5

= 3cm^2

Area of two window = 2× Area of window

= 2× 3

= 6cm^2

Total area of wall without window =40000cm^2- 6 cm^2

=39994cm^2

We know that,

Number of brick = volume of wall / volume of

brick

4700 = (area of wall × height of wall) (length× breadth× height of brick)

4700 = 39994cm^2× height / 4000cm^3

4700× 4000= 39994× height of wall

18800000cm^3= 39994 cm^2 × height of wall

18800000cm^3/ 39994 cm^2 = height of wall

Height of wall = 4707.06 cm

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