Question

(a) If A = 45° then show that tan 2A = 2 tan A 1-tan²A​

Answer 1

Answer:

A=30⇒2A=60

tan2A=

1−tan

2

A

2tanA

.

A=30 degrees

Show that:

tan60

∘

=

1−tan

2

30

∘

2tan30

∘

RHS:

1−tan

2

30

∘

2tan30

∘

=

1−

3

1

2×

3

1

=

2/3

2/

3

=3/

3

=

3

=tan60

∘

=LHS.