(a) If a and ß be two zeros of the quadratic polynomial
ax2 + bx + c, then evaluate
(1) 1/a³
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The polynomial is ax² + bx + c whose zeroes are α and β.
The sum of the zeroes = α+β = -b/a
The product of the zeroes = α.β = c/a
Therefore,
1/ a³ + b³
=> 1/ (a+b)³ - 3ab(a+b)
=> 1/ (-b/a)³ - 3c/a(-b/a)
=> 1/ -b³/a³+3bc/a²
=> 1/ -b³+3bc/a³
=> - a³/b³ + 3bc.
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