Question

a If a, ß are the roots of the equations ax² + bx+c = 0, then the quadratic equation whose roots are alpha/1+alpha and beta/1+beta
(A) (a-b+c)x² +(6–2c)x+c=0
(B) (a-b+c)X? -(6-2c)x+c=0
(C) (a-b+c)r? +(b– 2c)x-c=0
(D) None of these -​

Answer 1

Answer:

$(a - \: b + c) {x}^{2} + (b - 2c)x + c = 0$