Question

(a) If A is a point on y-axis whose ordinate is 5 and B is a point (-3, 1). Calculate
the distance between AB.

Answer 1

Answer:

Answer:

5 units

Step-by-step explanation:

Given : A is a point on the y-axis whose ordinate is 5 and B is the point (-3,1).

To Find: Calculate the length of AB.

Solution:

Since A is a point on the y-axis whose ordinate is 5.

Since A lies on y axis So, x -coordinate of Point A is 0.

Y -coordinate = ordinate = 5.

So, Point A = (x_1,y_1)=(0,5)(x

1

,y

1

)=(0,5)

Point B = (x_2,y_2)=(-3,1)(x

2

,y

2

)=(−3,1)

So, to find the distance between Point A and point B we will use distance formula :

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}d=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

Substitute the given values .

d=\sqrt{(-3-0)^2+(1-5)^2}d=

(−3−0)

2

+(1−5)

2

d=\sqrt{(-3)^2+(-4)^2}d=

(−3)

2

+(−4)

2

d=\sqrt{9+16}d=

9+16

d=\sqrt{25}d=

25

d=5d=5

Hence the length of AB is 5units

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