Question

a. If a number is divisible by 2 and 3, then the number is divisible by______.
b. If the sum of the digits of a number can be divided by with no remainder, the number is divisible by 9.
c. 1038 is divisible by 2, 3, and____.
d. A number is divisible by if its last three digits are divisible by 8 or are zeros.
e. 450 is divisible by 2, 3, 5, ____and____.​

Answer 1

Answer:

the answer is that

A. =4

B=(1,2,3,4,5,6,7,8,9,)

Answer 2

$\huge \orange { \bf Solution :- }$

Note :- Your respective answers are marked with green .

a. If a number is divisible by 2 and 3, then the number is divisible by $\bf \green {6}$

• $\bf \blue {Reason}$ :- By the divisibility test of 6 we knows that if a no. is divisible by both 2 , 3 it is also divisible by 6

b. If the sum of the digits of a number can be divided by 3 , with no remainder, the number is divisible by 9 $\bf \green {False}$

• $\bf \blue {Reason}$ :- It is false , since 3 can be written as 03 and sums of digit is 3 , which is not divisible by 9

c. 1038 is divisible by 2, 3, and $\bf \green 6$

• $\bf \blue {Reason}$ :- By the divisibility test of 6 we knows that if a no. is divisible by both 2 , 3 it is also divisible by 6

d. A number is divisible by 8 , if its last three digits are divisible by 8 or are zeroes $\bf \green {True}$

• $\bf \blue {Reason}$ :- By divisibility test of 8 we knows that a no. is divisible by 8 if and only it's last three digits ( HTO ) are divisible by 8 or are zeroes .

e. 450 is divisible by 2, 3, 5, $\bf \green 6$ , $\bf \green 9$ and $\bf \green {10}$

• $\bf \blue {Reason}$ :- As it is divisible by 2 , 3 it is divisible by 6 and also the sums of all digits is divisible by 9 , so it is divisible by 9 and last digit is zero , so also divisible by 10 .