Question

a
If
a1x+b1y=4
and
a2x+b2y=c2 are two pair of Linear
b.
equations in two variables then
a1/a2 not equql to b1/b2
1) It has unique solution
2) It has Intinite solution
3) It has no solution
4) None​

Answer 1

Answer:

a1x+b1y=4 (given)

a2x+b2y=c2 (given)

Also,

a1/a2 $\neq$ b1/b2 (given)

If a1/a2 is not equal to b1/b2, then the equations always have a unique solution.

Therefore, the given pair of linear equations will have a UNIQUE SOLUTION.

OPTION 1 is the correct answer

Step-by-step explanation:

1) When represented graphically, the lines of a pair of linear equations which have a UNIQUE SOLUTION will intersect at ONE UNIQUE POINT. Lines of two linear equations will only intersect at ONE UNIQUE POINT if their coefficients follow the following rule: a1/a2 $\neq$ b1/b2

2) When represented graphically, the lines of a pair of linear equations which have INFINITE SOLUTIONS will COINCIDE ON EACH OTHER. Lines of two linear equations will only COINCIDE ON EACH OTHER if their coefficients follow the following rule: a1/a2 = b1/b2 = c1/c2

3) When represented graphically, the lines of a pair of linear equations which have NO SOLUTIONS will BE PARALLEL TO EACH OTHER. Lines of two linear equations will only BE PARALLEL TO EACH OTHER if their coefficients follow the following rule: a1/a2 = b1/b2 $\neq$ c1/c2

On examining the above three possibilities, we come to know that the pair of linear equations given in the question follow the first criteria. therefore, the given pair of linear equations will have only one unique solution. OPTION 1 IS THE CORRECT ANSWER

Hope it helped! :)  Please upvote :)