Question

(a) If a² + b2 = 13, then write any one pair of values of a and b satisfying the
condition.

(b) Using the information in (a), construct a right angled triangle with hypotenuse
√13 cm.


please answer this question....

Answer 1

2² + 3² = 13   a & b are  2 & 3

Step-by-step explanation:

a² + b2 = 13,

using hit and trial method

2² + 3² = 13

a = 2

b = 3

or

a = 3

b = 2

hypotenuse √13 cm.

Perpendicular² +  Base²  =  hypotenuse²

now using 2² + 3² = 13

=> Perpendicular  & Base would be  2 & 3

Step 1 : Draw a line segment = 2 cm

Step 2: Draw an angle of 90 deg at one end of line draw.

Step 3: Take length = 3 cm at angle drawn in 2nd step

Step 4: join the ends to get a right angle triangle with hypotenuse √13 cm

Learn More:

Construct a right angled triangle ABC with hypotenuse BC = 3 cm ...

https://brainly.in/question/5060153

Construct a right-angled triangle whose hypotenuse is 6 cm long ...

https://brainly.in/question/11912912

Answer 2

Part A) The value of a is 2 and b is 3

Part B) Please find attachment

Step-by-step explanation:

Part a) $a^2+b^2=13$

If we write as sentence above equation.

"Sum of square of two number is 13". Two numbers are a and b

If we split 13 as 4 and 9

4 + 9 = 13

$2^2+3^2=13$

Compare with original equation

$a^2+b^2=13$

So, a = 2 and b = 3

Part B) Pythagoerous theorem

$a^2+b^2=c^2$

where, a and b are two legs and c is hypotenuse.

So, sides of right triangle are 2,3 and $\sqrt{13}$

Please find attachment for graph.

• Two legs, a= 2 and b =3

• Hypotenuse,  $c=\sqrt{13}$

#Learn more:

https://brainly.in/question/6780089