Question

(a) If AB=6 cm, BC= 8 cm, find AC
8. A gardener has 1000 plants. He wants to plant these in such a way that the number
of rows and the number of columns remain same. Find the minimum number of
plants he needs more for this.​

Answer 1

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__________________

Answer 2

Answer:-

Given,

Total plants = 1000

Number of rows is equal to the number of columns

Let number of rows = x

number of columns = x

Now,

Total plants = Number of rows × Number of columns

⇒1000 = x × x

⇒1000 = x²

⇒x² = 1000

⇒x = √1000

Finding square root of 1000 using long division method

[ the long division method is in attachment]

Then, we get the remainder is " 39 "

Given that:-

He wants to plant these in such a way that the number of rows and the number of columns remain same, we need to find the minimum number of plants he needs " more " for this.

We need to find:-

The least number that must be added to 1000 so at to get a perfect square.

Now,

31² < 1000 < 32²

Thus,

We add 32² - 1000 to the number

Number to added ⇒ 32² - 1000

                              ⇒1024 - 1000

                              ⇒24

Therefore, the gardener needs " 24 more plants "