)a)If cot θ = 1/√3, then find the value of (1- cos2 θ)/(2 - sin2 θ) .
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Answer:
Step-by-step explanation:
given cotA=1/√3
cotA=cot60
A=60
therefore (1- cos²θ)/(2 - sin²θ)
Putting the value of θ we get,
(1-cos²60)/(2-sin²60)
=1-(1/2)²/2-(√3/2)²
=1-1/4/2-3/4
=4-1/4/8-3/4
=3/4/5/4
=3/5
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