a) If logbase4, logbase3, logbase2, x = 0;
find x
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Let y = log4[log3[log2(x)]]
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Then::
4^y = log[3[log2(x)]]
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And:
3^(4y) = log2(x)
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So, 2^(12y) = x
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Solve for "y":
12y = log(x)/log(2)
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Ans:: y = (1/12)[log2(x)]
------
Then::
4^y = log[3[log2(x)]]
-----
And:
3^(4y) = log2(x)
----
So, 2^(12y) = x
======
Solve for "y":
12y = log(x)/log(2)
---
Ans:: y = (1/12)[log2(x)]
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