a) if p(x)=x2-7x+13.what is p(3).
write the polynomial p(x) - p(3) as
the product of two first degree
polyplomials:
C)
find the solutions of the equation
p(x)-p(3) =0
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Solution :-
→ p(x) = x² - 7x + 13
so,
→ p(3) = 3² - 7*3 + 13
→ p(3) = 9 - 21 + 13
→ p(3) = 22 - 21
→ p(3) = 1 (Ans.a)
now ,
→ p(x) - p(3) = x² - 7x + 13 - 1
→ p(x) - p(3) = x² - 7x + 12
→ p(x) - p(3) = x² - 4x - 3x + 12
→ p(x) - p(3) = x(x - 4) - 3(x - 4)
→ p(x) - p(3) = (x - 4)(x - 3) (Ans.b)
and,
→ p(x) - p(3) = 0
→ (x - 4)(x - 3) = 0
→ x = 4 , 3 (Ans.c)
Learn more :-
find three solutions for the equation 2x+3y=4
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