Question

(a) If the point (3, 4) lies on the graph of the equation 3y = ax + 7, find the value of a.

Answer 1

step by step explanation :

Solution:

Given: Linear equation 3y = ax + 7.

We can find the value of 'a' by substituting the

values of x and y in the given equation

By substituting the value of x = 3 and y = 4 in the

the equation 3y = ax + 7, we get

3(4) = a(3) + 7

12 = 3a + 7

3a = 5

a = 5/3

Hence, the value a = 5/

Answer 2

Answer:

The value of a is 5/3

Step-by-step explanation:

Equation= 3y=ax+7

The point (3, 4) lies on the graph of the equation

(x,y) = 3y=ax+7

(3,4) = ax-3y+7=0

x=3

y=4

a(3)-3(4)+7=0

3a-12+7=0

3a-5=0

3a=5

a=5/3