Question

(a) If the points (1,4), (3, y) and (-3, 16) are collinear
then the value of y is :
(1) 2
(ii)– 2 (iii) 3 (iv)-3​

Answer 1

area of triangle is 0

1/2[1(y-16)+3(16-4)-3(4-y)]

1/2[y-16+36-12+3y]

1/2(4y+8)

2(y+2)=0

y=-2

HOPE IT'S HELPFUL....

Answer 2

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Solution

Option number (ii) is the answer