Question

(a)
If (x + 5) is a factor of p(x) = x® – 20x + 5k then k = ?
(1. -​

Answer 1

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Answer 2

to find the value of X , equate it with 0.

x+5=0

x=0-5

x= -5

found the value of X as -5

Now given : p(x)=x^2 - 20 x + 5 k

substituting the value of X in p(x).

p(x)=x^2 - 20 x + 5 k

p(-5)= -5^2 - 20 (5)+ 5 k

=>25 - 100 + 5k

equating the result with 0 so as to find the value of K .

25-100+5k=0

-75+5k =0

5k =0+75

5k =75

k=75/5

_____

k= 15

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THEREFORE THE VALUE OF K IS 15.

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