(a) If x + y = 1, x3 + y3 = 4, then x2 + y2 = ..
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4
hence x2+y2= 3 if u didn't get feel free to ask
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Muski2:
plz mark as brainiest
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1
x³ + y³ = (x+y)(x² - xy + y²)
So substitute the values to get
x² + y² - xy = 4 ---(1)
(x+y)² - 3 xy = 4
So 1 - 3xy = 4
xy = -1
using (1) x² + y² = 3
So substitute the values to get
x² + y² - xy = 4 ---(1)
(x+y)² - 3 xy = 4
So 1 - 3xy = 4
xy = -1
using (1) x² + y² = 3
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