Question

a
If x+y+z=0 then find the value of (x+y)^3+(y+z)^3+(z+x)^3​

Answer 1

Answer:

x+y+z=0

=> x+y=-z

y+z=-x

z+x=-y

=> (x+y)³+(y+z)³+(z+x)³ = (-z)³+(-x)³+(-y)³

=> -(x³+y³+z³)

W.K.T, if x+y+z=0

then x³+y³+z³ = 3xyz

=> -3xyz