a immersion rod of 500 w is uesd to heat 15litre water in a plastic bucket. find the rise in temperature ,if this rod is uesd for 10 min and total heat produced is used to increase the temperAture (specific heat capacity of water is 4200j/kg c)
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The water fallen gains temperature and strikes bottom with an increased temperature, calculated as follows –
Given that the height of fall h = 50 m
Acceleration g = 10 m/ s 2
Let the water falling has a mass of m.
Thereby, the energy of water E is given by –
E = m g h
E = m x 10 x 50
E = 500 m
Now this is the amount of energy which is converted to the heat causing the rise in temperature, so we have –
E = δQ
E =δQ
E = m s δ T
Given s is the specific heat capacity of water as s = 4200 j / kg / C
E = m s δT
500 m = m 4200 δ T
δ T = 500 / 4200
δ T = 5 /42
δT = 0.12 degree C.
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