a immersion rod of 500 w is uesd to heat 15litre water in a plastic bucket. find the rise in temperature ,if this rod is uesd for 10 min and total heat produced is used to increase the temperAture (specific heat capacity of water is 4200j/kg c)
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Considering the system to be isolated from the surrounding.
Energy required to raise the temperature of water by 60 degrees is 2*4200*60=504KJ.
Power of heater=energy per unit time=504000/(100*60)=84W
Energy required to melt ice=0.5*334=167KJ
Time taken=167000/84= seconds.1988.09 s or 33.135 minutes
hope it helps you
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