CBSE BOARD X, asked by drgo37844, 8 months ago

a immersion rod of 500 w is uesd to heat 15litre water in a plastic bucket. find the rise in temperature ,if this rod is uesd for 10 min and total heat produced is used to increase the temperAture (specific heat capacity of water is 4200j/kg c)​

Answers

Answered by rajkumarh75
9

Answer:

Considering the system to be isolated from the surrounding.

Energy required to raise the temperature of water by 60 degrees is 2*4200*60=504KJ.

Power of heater=energy per unit time=504000/(100*60)=84W

Energy required to melt ice=0.5*334=167KJ

Time taken=167000/84= seconds.1988.09 s or 33.135 minutes

hope it helps you

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