A in a place where the mercury barometer reads 75cm wanted to make an alcohol barometer. If alcohol has a density of 800kgm. Find minimum length of the tube that would be used
Answers
Answer:
Height of the Mercury Column in a Barometer = 75 cm.
For Finding the Pressure in S.I. System, Changing 75 cm into meter.
∴ Height of the Mercury column(h) = 75 cm.
= 0.75 m.
Acceleration due to gravity(g) = 9.8m/s2
Density of the Water =103kg/m3.
=1000kg/m3
Specific Gravity of the Mercury = 13.6
Specific Gravity of the Substance is the Ratio of the Density of the Substance to the Density of the Water.
∴ Specific Gravity = Density of the Substance /Density of the Water.
⇒ Density of the Mercury(ρ) = 1.3×1000
= 1300kg/m3.
Now,
Using the Formula,
Pressure(P) = hρg
= 0.75×1300×9.8
= 9555 Pa.
Hence, the Pressure is 9555 Pa.
Explanation:
Height of the Mercury Column in a Barometer = 75 cm.
For Finding the Pressure in S.I. System, Changing 75 cm into meter.
∴ Height of the Mercury column(h) = 75 cm.
= 0.75 m.
Acceleration due to gravity(g) = 9.8m/s2
Density of the Water =103kg/m3.
=1000kg/m3
Specific Gravity of the Mercury = 13.6
Specific Gravity of the Substance is the Ratio of the Density of the Substance to the Density of the Water.
∴ Specific Gravity = Density of the Substance /Density of the Water.
⇒ Density of the Mercury(ρ) = 1.3×1000
= 1300kg/m3.
Now,
Using the Formula,
Pressure(P) = hρg
= 0.75×1300×9.8
= 9555 Pa.
Hence, the Pressure is 9555 Pa.
Answer:
Correct option is
B
2.5 km
Pressure differences between sea level and the top of hill
△p=(h1−h2)×pHg×g
=(75−50)×10−2×pHg×g ...(i)
and pressure difference due to h metre of air
△p=h×pair×g ...(ii)
By equating Eqs. (i) and (ii)
h×pair×g
=(75−50)×10−2×pHg×p
p=25×10−2(pairpHg)
=25×10−2×104=2500m
∴ Height of hill = 2.5 km