(a) In a process, 701 J of heat is absorbed by a system and 394 J of work is
done by the system. What is the change in internal energy for the process? (b)
Calculate the internal energy change when the system absorbs 5 KJ of heat and
1KJ of work
Answers
Answered by
37
Explanation:
ΔU = Q - W (First law of thermodynamics)
ΔU = internal energy change
Q = heat absorbed by the system
W = Work done by the system
a) Q = 701 J , W = 394 J
ΔU = ?
ΔU = Q - W = 701 J - 394 J = 307 J
307 Joules is the change in internal energy for the process.
b) Q = 5 kJ = 5000J , W = 1kJ = 1000 J
ΔU = ?
ΔU = Q - W = 5000 J - 1000 J = 4000 J = 4 kJ
4 kilo Joules is the change in internal energy for the process.
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Answer:
HOPE IT HELPS
Explanation:
THE ANSWER IS 4kj
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