Physics, asked by boyatchd2005, 3 days ago

A In an experiment, four quantities a, b, c and d are measured with percentage error 1%, 2%, 3% and 4%, respectively. Quantity P is calculated as follows P = a³b²/cd percentage error in P is ​

Answers

Answered by Anonymous
2

Solution:-

p =  \frac{a {}^{3}  {b}^{2} }{cd}

 =  >  \frac{Δp}{p}  = 3

 \binom{Δa}{a}  \times 100) + 2( \frac{Δb}{b}  \times 100) + ( \frac{Δc}{c}  + 100) + ( \frac{Δd}{d}  \times 100)

 =  > 3 \times 1 + 2 \times 2 + 3 + 4

 =  > 3 \times 4 + 3 + 4 = 14\%

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