Question

a) In Fig. 2, AP = PD and CP = PB. Show that
(1) AAPB ACPD
(ii) AB || CD
​

Answer 1

Answer:

(i) Given : In △APC and △DPB,

∠APC=∠DPB ...[Vert. opp. ∠s]

∠CAP=∠BDP ...[Angles subtended by the same arc of a circle are equal]

∴ By AA-condition of similarity,

△APC∼△DPB

(ii) △APC∼△DPB

So, sides are proportional

⇒

DP

AP

=

PB

CP

∴AP×PB=CP×DP

Step-by-step explanation:

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