Question

a. In the fig. ABC is an equilateral where AD ll EF . prove that FDbisects EC. ​

Answer 1

Step-by-step explanation:

$\frac{1}{2} bc \: = \frac{ ab}{2} = \frac{3ab}{6}$

and

$\frac{bc}{6} = \frac{ab}{6}$

∴ AD² = AB² / 36 + AB² - 9AB²/ 36

∴ 9AD² =7AB²

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Answer 2

Step-by-step explanation:

Step-by-step explanation:

$\frac{1}{2} bc \: = \frac{ ab}{2} = \frac{3ab}{6}$

and

$\frac{bc}{6} = \frac{ab}{6}$

∴ AD² = AB² / 36 + AB² - 9AB²/ 36

∴ 9AD² =7AB²

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