Question

a. In the figure alongside AB-AC and AD is bisector of LA. Prove that
(0) Dis the midpoint of AC
(ii) AD IBC
(G)
B
10 с​

Answer 1

Answer:

hello

it would be better is diagram is given

Step-by-step explanation:

In the given figure, If AD is the bisector of ∠A, then

∠BAD=∠CAD⇒BD=CD

And It is given, that  AB=AC

∴∠B=∠C

Therefore △ABD and △ACD are congruent by ASA and SAS

Hope Helpful...