Question

(a) In the figure given below, O is the centre of the circle and AB is a diameter.
If AC = BD and AOC = 72o
. Find:
(i) ABC
(ii) BAD
(iii) ABD

Answer 1

Answer:

its easy

Step-by-step explanation:

AOC=72°

ABC=AOC (opposite angles)

72°=72°

ABC+ABD=180°(linear pair)

or,ABD=180°-72°=108°

ABC=BAD (opposite angles)

72°=72°

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Answer 2

Answer:

ABC&BAD=72°

ABD=108°

Step-by-step explanation:

AOC=72°

ABC=AOC (opposite angles)

72°=72°

ABC+ABD=180°(linear pair)

or,ABD=180°-72°=108°

ABC=BAD (opposite angles)

72°=72°

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