Question

a) In the figure, O is the centre of the circle and <ACD= 30°. Find:
(i) <BAD
(ii) <AOD
[3]
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Answer 1

Answer:

angleACD= angleABD=30°. [ angles in the same segment]

angleADB=90°. [ angle in a semi circle]

in triangleABC

angleABD+angleADB+angleBAD=180°. [ angle sum property]

angleBAD=60°

construction- Join OD

angleAOD=2angleACD. [ angle at the centre is twice the corresponding inscribed angle]

angleAOD=60°

Hope it helps