Question

(a) In the following velocity-time graph find the total distance travelled by the body. Also tell what type of
motion is represented by the part AB
please help me
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Answer 1

Explanation:

so here distance is equal to velocity under the graph so

in 0 to 5 sec distance travelled by the body = area of the triangle =1/2×5×10= 25 m

in 5 to 10 sec distance travelled by the body =area of the rectangle = 10×5 50 m

in 10 to 16 second distance travelled by the body = area of the triangle =1/2×6×10 = 30 m

so total distance travelled by the body = 25+50+30 = 105m

the motion in part AB is linear motion constant motion where the velocity does not change with time

Answer 2

Answer:

The total displacement is 105m.

Explanation:

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