(a) In the given figure, AB = BE and AXB
is the diameter of the circle ACBD,
centre X.
Prove that
(i) CD = CE
(ii) XC || DE
(iii) XC bisects ZACD
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CD = CE & XC ║ DE In the given figure, AB = BE and AXB is the diameter of the circle
Step-by-step explanation:
AB = BE
=> ∠BAE = ∠BEA
=> ∠BAC = ∠DEC
∠BAC = ∠BDC ( angle by same chord BC)
=> ∠BDC = ∠DEC
=> ∠EDC = ∠DEC
=> CD = CE
AX = XC
=> ∠CAX = ∠ACX
∠CAX = ∠BAE
=> ΔAXC ≈ ΔABE
=> AX/AB = AC/AE = XC/BE
=> XC ║ BE
=> XC ║ DE
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1
Answer:
given above
Step-by-step explanation:
watch. it carefully u wil. get it correctly..thank u
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