Question

A
In the given figure
. AP= 30 cm then find
the perimeter
/
of Abc​

Answer 1

Answer:

From the given diagram we can see that AP = 10cm

If AP = 10 the AQ = 10 Because AQ and AB are the tangent to the circle from a common point A

Similarly, PB = BM and CM =CQ

Also, AP =AB + PB and AQ = AC + CQ

To find the Perimeter of triangle ABC

Perimeter of ABC = AB + BM + CM + AC

= AB + PB + CQ + AC (since PB = BM and CM =CQ)

= (AB + PB) + (CQ + AC)

= AP + AQ =10 +10 =20cm

Therefore Perimeter of triangle ABC =20 cm