-a. In the given figure DE || BC. If DE = 4cm, BC = 6 cm and ar (angle ADE) = 20 cm2
find the area of AABC.
А
With proper steps
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Answered by
0
Answer:
How to solve your question
Your question is
2
0
+
3
(
2
−
3
)
=
4
7
20+3(2p-3)=47
20+3(2p−3)=47
Solve
1
Distribute
2
0
+
3
(
2
−
3
)
=
4
7
2
0
+
6
−
9
=
4
7
2
Subtract the numbers
2
0
+
6
−
9
=
4
7
1
1
+
6
=
4
7
3
Rearrange terms
1
1
+
6
=
4
7
6
+
1
1
=
4
7
4
Subtract
1
1
11
11
from both sides of the equation
6
+
1
1
=
4
7
6
+
1
1
−
1
1
=
4
7
−
1
1
5
Simplify
Subtract the numbers
Subtract the numbers
6
=
3
6
Step-by-step explanation:
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Answered by
2
Answer:
ok no problem only branly
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