Question

(A)in triangle PQR, PQ=PR, angle Q=80°, then angle P= 40° (R) angles opposite to equal sides are always equal​

Answer 1

Answer:

Given, PQ = QR

Thus, ∠QPR=∠PRQ=x (Isosceles triangle Property)

Sum of angles of triangle = 180

∠PQR+∠PRQ+∠QPR = 180

80+x+x=180

2x=100

x=50°

 ∠R=50°  

Answer 2

Answer:

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