a income is 10% more than b income by how much percent is b income less than that of a
Answers
Answered by
5
Let B income be x
So, A income = 10% + x
Loss = x - 10x / 100
= - 9x / 100
Percent Of Decrease = Loss / 100 * CP
= - 9x / ( 100 * 100 ) * x
= - 9x / 10000 * x
= - 9 x ^ 2 / 10000
So, A income = 10% + x
Loss = x - 10x / 100
= - 9x / 100
Percent Of Decrease = Loss / 100 * CP
= - 9x / ( 100 * 100 ) * x
= - 9x / 10000 * x
= - 9 x ^ 2 / 10000
Answered by
5
let income b be x
so, 10/100×b + b= a
b/10 + b= a
(b+10b)/10 =a
11b/10=a ...eq 1
like this solve for b and put the value of a
u will get your answer,
hope it helps u
please mark my answer as brainliest
so, 10/100×b + b= a
b/10 + b= a
(b+10b)/10 =a
11b/10=a ...eq 1
like this solve for b and put the value of a
u will get your answer,
hope it helps u
please mark my answer as brainliest
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