A inductor of 5H inductance carries a steady current of 2A.How can 50V self induced emf be made to appear in the inductor?
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Answer:
The induced emf can be produced by decreasing the current to zero at 0.2 s
Explanation:
According to the problem the inductance of the inductor,p is 5H
it carries 2A of current.
p = 5H
induced emf= 50V
pdI/dt= 50
dt= p x dl/50
=> dt= 5 x 2/50
= 0.2 s
Therefore the induced emf can be produced by decreasing the current to zero at 0.2 s
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