a insect moves in such a way that it os always at a distance of 1 cm from sides of square if insect is always outside the circle then find the distance covered by inscet in 10 rounds side of square is 28cm . no spam
Answers
Answer:
please mark me brainlist��
Step-by-step explanation:
The Cyclotron Autoresonance Maser (CARM) is a well-known variety of FEMs. Unlike the ubitron in which electrons move in a periodical undulator field, in the CARM the particles move along helical trajectories in a uniform magnetic field. Since it is much simpler to generate strong homogeneous magnetic fields than periodical ones for a relatively low electron energy ({Brit_pounds}{le}1-3 MeV) the period of particles` trajectories in the CARM can be sufficiently smaller than in the undulator in which, moreover, the field decreases rapidly in the transverse direction. In spite of this evident advantage, the number of papers on CARM is an order less than on ubitron, which is apparently caused by the low (not more than 10 %) CARM efficiency in experiments. At the same time, ubitrons operating in two rather complicated regimes-trapping and adiabatic deceleration of particles and combined undulator and reversed guiding fields - yielded efficiencies of 34 % and 27 %, respectively. The aim of this work is to demonstrate that high efficiency can be reached even for a simplest version of the CARM. In order to reduce sensitivity to an axial velocity spread of particles, a short interaction length where electrons underwent only 4-5 cyclotron oscillations was used in this work. Like experiments, a narrow anode outlet of a field-emission electron gun cut out the {open_quotes}
Step-by-step explanation:
s =1 cm
after such 15 cycle
s equal to 1*15 t =15 sec
when it climb 3 cm it will reach at top
therefore t equal to 15 + 1 =16sec displacement equal to 18 distance equal to 5*7+3 =33
mark as brilliant and also subscribe to pratikkumar_yt