(a) Insert 3 geometric m4earns between 1/9 and 9 . (b) if a, ar,ar^2, ar^3.... Be in G.P. find the. Common ratio.
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Step-by-step explanation:
(a)
Let a₁,a₂,a₃ be 3 geometric means between (1/9) and 9.
The Sequence will be (1/9), a₁, a₂, a₃, 9 are in G.P.
Here, a = (1/9).
Now,
⇒ 9 = (1/9) * r⁴
⇒ 3² = 3⁻² * r⁴
⇒ 3⁴ = r⁴
⇒ r = 3
Then,
a₁ = (1/9)
a₂ = ar = (1/3)
a₃ = ar² = 1
a₄ = ar³ = 3
a₅ = ar⁴ = 9.
Hence (1/3), 1,9 are the three geometric means.
(b)
The general form of the G.P is a, ar, ar², ar³.
Here,
a is called as the first term.
r is called as common ratio.
Hope it helps
nishajoshi1298:
Thk u
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