Question

a integer is chosen between 1 and 100 by the probability that it is divisible by 8 and not divisible by 8

Answer 1

In the question it is Given that the  numbers are "between 1 and 100", we should exclude both 1 and 100.So we are left with 98 numbers.

i) Total numbers BETWEEN 1 and 100 are 98
Total Number of Outcomes= 98
Number divisible by 8 are : 8,16,24,32,49,48,56,64,72,80,88,96
Number of favourable outcomes = 12
Probability = Number of favourable outcomes / Total number of outcomes
Probability (divisible by 8) = 12/98 = 6/49
P((divisible by 8) = 6/49

ii) Number not divisible by 8 are : 98 -12 = 86
Number of favourable outcomes = 86
Probability = Number of favourable outcomes / Total number of outcomes
Probability (not divisible by 8) = 86/98 = 43/49
P((not divisible by 8) = 43/49

HOPE THIS WILL HELP YOU….

Answer 2

Solution :-

Total number of integers between 1 and 100 are 98 (excluding 1 and 100).

Total number of outcomes = 98

Numbers which are divisible by 8 = 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88 and 96

So, total number of favourable outcomes = 12

1) Probability (numbers divisible by 8) = Total number of favourable outcomes/Total number of outcomes

⇒ 12/98

= 6/49

Numbers which are not divisible by 8 = 98 - 12 

= 86

2) Probability (numbers not divisible by 8) = 86/98

= 43/49

Answer.