Math, asked by shreeya64, 10 months ago

A invested 125% as much money as B. C invested 80% as much money as B has. The total of all the three is 61,000. How much did C invest?​

Answers

Answered by mishra96250
1

Answer:

Let x be the investment of B

From the given information, we have

Investment of A

=

125

%

o

f

x

=

1.25

x

Investment of C

=

80

%

o

f

x

=

0.85

x

Total of all the three

=

61

,

000

1.25

x

+

x

+

0.8

x

=

61

,

000

3.05

x

=

61

,

000

x

=

61000

3.05

x

=

20000

Investment of

C

=

80

%

o

f

20000

=

0.8

X

20000

=

16000

Hence, C invested

16000

Answered by windyyork
2

Hence, C invest Rs. 16000.

Step-by-step explanation:

Since we have given that

A invested 125% as much money as B

So, ratio becomes,

\dfrac{A}{B}=\dfrac{125}{100}=\dfrac{5}{4}

C invested 80% as much money as B has.

\dfrac{B}{C}=\dfrac{100}{80}=\dfrac{5}{4}

So, Ratio of A to B to C would be

A  :   B  :  C

5  :    4

         5 :   4

-------------------------------

25  :  20  : 16

Total of all the three = Rs. 61000

So, Amount of C invested is given by

\dfrac{16}{61}\times 61000\\\\=Rs.\ 16000

Hence, C invest Rs. 16000.

# learn more:

Tom’s salary is 125% of Tina’s salary. Tito’s salary is 80% of Tina’s salary. The total of all the three salaries is Rs.61,000. What is Tito’s salary?

https://brainly.in/question/6266201

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