A invested Rs 4500 for 3 years at the rate of 8% annual compound interest and B invested the
same amount for same time at the rate of per month per rupee I paisa simple interest. Calculate
(i) The interest received by A. (ii) The interest received by B.
Answers
Answered by
4
Step-by-step explanation:
Answer
Given,
Rate =
100
5
×100=5%
S.I.=
100
PRT
=
100
4500×5×2
=450Rs.
A=P+SI=4500+450=4950 Rs.
Answered by
7
Answer:
solution,here
Step-by-step explanation:
p=4500
t=3yrs
r=8%
Now,
CI=p(1+r÷100)^t-1
= 4500(1+8÷100)'3-1
=4500*0.2597712(multiplying (1+8%100'3-1)
=Rs.1168.70
Hence,interest received by A is Rs.1168.70
Again,
P=4500
t=3yrs
r=1paisa per rupee per month =1÷100*100=1%
again,
annually rate=1*12=12%
now,
SI=PTR/100
=4500*3*12/100
=Rs.1620
Hence,the interest recevied by B is Rs.1620
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