Math, asked by neerutakayc, 4 months ago

A invested Rs 4500 for 3 years at the rate of 8% annual compound interest and B invested the
same amount for same time at the rate of per month per rupee I paisa simple interest. Calculate
(i) The interest received by A. (ii) The interest received by B.​

Answers

Answered by rathorenishant84
4

Step-by-step explanation:

Answer

Given,

Rate =

100

5

×100=5%

S.I.=

100

PRT

=

100

4500×5×2

=450Rs.

A=P+SI=4500+450=4950 Rs.

Answered by ramusunar56a
7

Answer:

solution,here

Step-by-step explanation:

p=4500

t=3yrs

r=8%

Now,

CI=p(1+r÷100)^t-1

= 4500(1+8÷100)'3-1

=4500*0.2597712(multiplying (1+8%100'3-1)

=Rs.1168.70

Hence,interest received by A is Rs.1168.70

Again,

P=4500

t=3yrs

r=1paisa per rupee per month =1÷100*100=1%

again,

annually rate=1*12=12%

now,

SI=PTR/100

=4500*3*12/100

=Rs.1620

Hence,the interest recevied by B is Rs.1620

Similar questions