Math, asked by harshitnagmula, 11 months ago

A invests 768 more than B in a business but B has invested his capital for 7 months. While A has invested his capital for 4 months, if the share of A is 42 more than B out of total profit of 358. FInd the amount Invested by B

Answers

Answered by sanjeevk28012
3

Answer:

The amount invested by B is Rs 632  .

Step-by-step explanation:

Given as :

Total profit earn = Rs 358

The share of A is Rs 42 more than that of B share

Let The B share = Rs y

So, A's share = Rs y + rs 42

Let The investment amount of B = Rs x

A invest Rs 768 more than B

So, The investment amount of A = Rs 768 + Rs x

The time period of investment for B = 7 months

The time period of investment for A = 4 months

According to question

Amount invested by B × time period of investment for B : amount invested by A × time period of investment for A

i.e Rs x × 7 : Rs (768 + x) × 4

Or, 7 x : (768 + x) 4

Again

Total profit earn = A' share + B' share

i.e y + 42 + y = 358

Or, 2 y = 358 - 42

or, 2 y = 316

∴   y  = \dfrac{316}{2}

i.e y = 158

So, B's share = y = Rs 158

So, A's share = y + 42 = Rs 200

Again

B's share = \dfrac{7x}{7x + 4 x + 3072}  × total profit

Or, \dfrac{7x}{11x + 3072}  × rs 358 = Rs 158

Or.

Or, 7 x × 358 = 11 x × 158 + 3072 × 158

Or, 2506 x - 1738 x = 485376

Or, 768 x = 485376

∴  x = \dfrac{485376}{768}

i,e x = rs 632

So, The amount invested by B = x = Rs 632

Hence, The amount invested by B is Rs 632  . Answer

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